Reply To: Challenge 10B

20th January 2026 at 2:04 pm #115139

_madness_

Participant

If we are all bragging about our Python coding, here is something that will decrypt 10B:


c = "7CXS3 H6S7C KSXDA S2CKS...".replace(" ","")
p = ""
for i in range(len(c)//4):
    n = ["A23456789XJQK".index(c[4*i+2*j+0]) + 13*"CDHS".index(c[4*i+2*j+1]) - 36*j for j in [0,1]]
    p += "SHADOWBCEFGIKLMNPQRTUVXY"[(n[0]%6) + 6*(n[1]//4)] + "FULHEARTBCDGIKMNOPQSVWXY"[(n[1]%4) + 4*(n[0]//6)]
print(p)

I will not be taking questions at this time.