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[The-Letter-Wriggler]

5A recap
512 pictograms outlined, the remaining
248 were not. (512+248=760) (why not 251 to give 763?)

512 being 9 binary digits of 0’s and 1’s
(000000000->111111111 = 0->511)
248 being 9 binary digits of 0’s to 7 digits of 1’s plus 2 digits of 0’s
(000000000->111111100 = 0->508)

with and without grid (add left most 0 or 1, 0000000000 – 1111111100 10 bits)
0000000000 1111111100 = 0-1020 decimal, final range 512+509= 1021

The reading is to be left to right and down so box 23 is

1 0 1
1 0 0
0 1 1

= 101 100 011 giving (10 digit binary)
(0)101100011 = 355 decimal if it has a grid
(1)101100011 = 867 decimal if it has no grid

Disclaimer: This is my own workings it may or may not be correct.