Reply To: Maths
Excellent question USB-C_is_supreme. Here are my thoughts along the same lines as the previous solutions provided…
Given a! + b! = 2^n
1. If a = b, then:
2a! = 2^n
a! = 2^(n-1)
No solution for a >= 3, as 3 is not a factor of 2^(n-1).
2. If a < b, then:
a!(1 + b!/a!) = 2^n, as a! is a factor of b!.
No solution for a >= 3, as 3 is not a factor of 2^n.
3. If a > b, then:
The same applies as 2 above, but with a and b swapped.