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The National Cipher Challenge

Reply To: Programming

#98417
Astralica
Participant

@ByteInBits

Is this correct? (For the replacement ones.)
Honestly, it’d probably be easier to do it manually, but here’s the result my code gives.
c8a03543e09418b43116ea62ed2dd0b6
9801ec0d80cdae27abc84c53844cb7b0
e7a6e8c0943b4c986ddd92ad762be009
db9f2879c024590ca4f97812f7aa2dcd
744fa68f2e80a0c13ef4b821ca60e3a7

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