Reply To: Yet another 10B post
So…been round the houses too many times on this one!
But, have transposed the original cipher to get /|\ in each group of three using 21 columns.
Then sequenced in pairs to get fewer than 36 different combinations when grouped in 7 columns of 2 letters, but there are 7 different alphabets used.
They all look like simple substitution ciphers but I can’t get a decent massage so far…is this on the right track?
Interesting! Harry