- This topic has 22 replies, 23 voices, and was last updated 1 month, 2 weeks ago by Mattyrat2027.
11th December 2022 at 2:19 pm #87519Mattyrat2027Participant
I am highly confident that I have found the first step to decryption, having looked at the factors and blocks, but I don’t know where to head from there. Look forward to these tips, Harry11th December 2022 at 2:19 pm #87520f6exbParticipant
I know that weekend is used to rest, but it’s nice this year that the Elves answer questions to help people blocked.11th December 2022 at 5:41 pm #87532floatingyunsanParticipant
If anyone is struggling with 9B I can assure you that 8B was a whole lot worse. 9B really isn’t that complex. Here’s my tip: do think of it simply, the simpler you think about it the easier it is. I over complicated it a bit at first. When you get the decrypt but it’s not quite right (you’ll see why) let me know I can direct from there, good luck everyone!!! All the best x12th December 2022 at 9:00 am #87508dweglowski2Participant
Harry can remove parts if nessesary (please be kind).
First of all look at the group sizes.
You will see that the first block is a different size to the others.
This normally is found at the end (hinting at the text being reversed).
Secondly when you have done the first step try to identify the cipher.
Cribbing is extremely useful.
We know from the hint that it is signed off by Abraham Woodhull so try arrange the letters to keep that at the end of your decrypt.
It should be quite plain sailing from there.
Overall it isn’t double encrypted to the point you expect, it is quite a lot simpler of a first cipher.12th December 2022 at 9:00 am #87498f6exbParticipant
Reread all the 9B advice, but in particular the second paragraph.
Look at the structure of the first groups and their letters.
Factorize the length of the text and use the smallest ones.12th December 2022 at 12:00 pm #87522Dvorak365Participant
Once you’ve worked out what the length of the starting chunk means for the text, I would suggest encrypting the crib with a transposition cipher.
Then some pattern spotting should lead you towards the solution. I would warn against brute force attempts.12th December 2022 at 1:08 pm #87539BluePumpkinParticipant
how do we start the first part?12th December 2022 at 5:00 pm #87526A1PHA_L3G3NDParticipant
After the first encryption, we know that the letter should be signed by Abraham Woodhull, but we know that’s not in the right place. A little tweaking of the text is in order.
All the help I can give.12th December 2022 at 5:00 pm #87530f6exbParticipant
This means that a letter is missing for the text to be a multiple of 5.12th December 2022 at 7:29 pm #87540traingirlParticipant
Apologies for post #87495. I forgot about one step I had done. It was indeed double encrypted.12th December 2022 at 7:29 pm #87542Mattyrat2027Participant
The problem, I find, with transposition ciphers is that there are so many variations on how to perform one, e.g. Write by rows and read by columns, write by columns and read by rows etc.13th December 2022 at 9:00 am #87531YeetcadamyParticipant
If the last block usually has less than five characters, what sort of thing could have caused the last block to become the first. Additionally, you might want to break the text into equally sized sections and try to find ABRAHAMWOODHULL, or an anagram of it in one of those sections.
Harry do feel free to censor anything if you feel you need to13th December 2022 at 9:00 am #87529Mattyrat2027Participant
[omit if not allowed] It’s reversed (?)13th December 2022 at 9:00 am #87528BobDParticipant
Seems rather ‘back-to-front’!13th December 2022 at 9:00 am #87485madnessParticipant
It is with regret that I will have to decline your request for hints.
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