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The National Cipher Challenge

Sunday puzzle 5:

Making connections

Clearing out a cupboard at BOSS Technical Stores has unearthed a box of old signal adaptors from one of our legacy field systems.

The system used six different kinds of connection, labelled A to F. Each adaptor joins one type of connection to another and can be used either way round.

There are twelve adaptors in the box:

A – DB – EC – FA – E
B – DD – FB – CE – F
A – FC – EC – DB – F

The old service manual says that the diagnostic equipment could test the entire set in a single run by joining all twelve adaptors into one continuous chain.

There is only one rule: adjoining ends must carry the same letter.

So, for example, an A – D adaptor could be followed by D – F, which could then be followed by F – C.

Can you arrange all twelve adaptors into a single unbroken chain? You must use every adaptor exactly once. You may turn any adaptor round.There is also a second question.

What letters must appear at the two free ends of your finished chain? Can you work that out before you find the chain?

Hint 1

Count how many times each of the letters A, B, C, D, E and F appears among the twelve adaptors.

Hint 2

Think about any letter that appears somewhere inside the completed chain.

Every time the chain arrives at a connection of that type, it must also leave through another one. What does that tell you about letters that occur an odd number of times?

Bonus challenge: could the twelve adaptors ever be joined into a closed loop, with no free ends at all? Explain your answer.

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