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The National Cipher Challenge

Reply To: Maths

#97445
CaldewBA-Alfie
Participant

Here’s my solution:
From 4*A=D and A+C=D we can gather that C = 3*A
If 3*A=C and A*B=C then B must be 3
If C-B=B and B=3 then C-3=3. If we rearrange this we can get 3+3=C so C=6
Since C=3*A then we know that A=2 because 2*3=6 (This comes from A*B=C, we know that C=6 and that 6/3=A so A=2)
D=4*A, which we now know is 2 so 4*2=8=D
A=2,B=3,C=6,D=8
This was a nice, easy puzzle that only takes a minute or two to solve, with a simple logic behind it but can still be quite intimidating towards people who don’t understand how to approach it.
(Please feel free to correct me if I’m wrong since I didn’t spend very long but I am quite certain that I got it right)

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