Skip to main content

8b

Tagged: 

  • This topic has 17 replies, 12 voices, and was last updated 1 month, 2 weeks ago by The-Letter-Wriggler.
Viewing 15 posts - 1 through 15 (of 21 total)
  • Author
    Posts
  • #87418
    someone
    Participant

    any help on 8b

    #87422
    Yeetcadamy
    Participant

    I think it’s a form of a transposition cipher, because the frequency of letters matches the english language, but I cannot get it to work. The size of groups is either 5 or 7 as the total number of characters is 5 or 7

    #87425
    Ellie05
    Participant

    i would my friend but im just as stuck as you 🙁

    #87434
    A1PHA_L3G3ND
    Participant

    From the helpful comment given by Madness, it could be some version of the porta cipher called the quagmire IV to be specific.

    [Just to be clear, posting this does not mean it is right! Harry
    ps (or wrong!)]

    #87437
    sb
    Participant

    This one is really challenging. I do think it’s a transposition but I can’t make it work. I’ve got the first 5 letters – I think – but the rest of it doesn’t make sense. I could really appreciate some help with it.

    #87436
    f6exb
    Participant

    The size of groups can also be 35 or 41, but I cannot get it to work.

    #87444
    f6exb
    Participant

    After debugging my program, so far so good.

    #87445
    The-Letter-Wriggler
    Participant

    This is embarrasing, I too have not yet solved 8B.

    The tips say: Factors are your friend!
    I broke the text into blocks and encrypted each block separately. . .

    The factors are 5, 7 and 41.
    I have tried both a Normal Transposition and
    a Columnar Transposition in the following ways
    Write by Rows Read by Columns (normal way)
    Write by Rows Read by Rows
    Write by Columns Read by Rows
    Write by Columns Read by Columns

    Using 35 blocks of 41 letters
    I have only been able to obtain the first 8 WORDS

    Is this a new take on the transposition cipher Harry?

    [Beginning to look like it! Harry]

    #87449
    madness
    Participant

    1. It is not a Porta or even a quagmire.
    2. It is a transposition.
    3. Each block is encrypted the same way.
    4. The key is short enough that you can brute-force it.
    5. The blocks are 35 letters.

    Harry can censor as much of that as he likes.

    #87451
    f6exb
    Participant

    @TLW
    “Using 35 blocks of 41 letters
    I have only been able to obtain the first 8 WORDS”

    How can you write 41 letters in a rectangle ?

    #87454
    ciphercutter
    Participant

    Censor as required.
    I always start transposition ciphers by breaking into a grid.
    Am I aiming for 35 across the top by 41 down?
    41 across and 35 down?
    Or something else entirely?

    #87455
    The-Letter-Wriggler
    Participant

    Funny old world isn’t it – five mins after my post above I solve it, duh!

    #87457
    msjjmathsicloud-com-1
    Participant

    Eureka. Thanks for the pointers Madness. Made some progress at the weekend but your post today helped me immensely.

    #87456
    ADecipher
    Participant

    What are blocks in a transposition cipher?

    [The blocks are the units you break the letters into in order to encrypt it.

    So if the text had sixty letters, you might break it into 4 blocks of fifteen letters each, then encrypt each block separately:

    THEBL
    OCKSA
    RETHE

    UNITS
    YOUBR
    EAKTH

    ELETT
    ERSIN
    TOINO

    RDERT
    OENCR
    YPTIT

    Hope this helps, Harry]

    #87458
    ciphercutter
    Participant

    Well feel free to censor the entirety of my previous transmission. I have finally cracked it.

Viewing 15 posts - 1 through 15 (of 21 total)
  • You must be logged in to reply to this topic.
Report a problem